algorithm - Loops in C challenge: can it be done another way? -

hi c experts (please don't shoot, i'm no c programmer anymore time time have question pops in mind)

the "simplest" , logical answer

for (x = end; x >= 0; --x) {     printf("%c", word[x]); }

but wondering if there wasn't way achieve same goal staying closer original loop poseted:

for (x = word[end]; x >= word[0]; x--) {     printf("%c", x); }

i don't know enough c work out, couldn't play arrays pointers loop through

char * wordp; for(wordp = &word[end]; /*something*/; wordp--){\    printf("%c", &wordp); }

p.s.: don't care if forwards or backwards loop.

p.p.s.: sorry if made obvious c mistakes in pointers; point them out in comment , i'll edit them. ;)

jason

absolutely.

char *wordp;  for(wordp = word + end; wordp >= word; wordp--){    printf("%c", *wordp); }

shell