visual studio 2008 - to count the no of days present and absent -


i have stored employee's attendance following.....

columns  :  employeecode day1   day2   day3 ................ day31  values     :  ec001      p       p

for purpose need present day count & absent day count every employee. how it?

hi copy , paste code , work fine. check if change table name have in database. please don't forget vote if helps. thank you!

declare @tablename varchar(100) declare @tablefieldid varchar(100)  set @tablename = 'tbl_attendance' set @tablefieldid = 'employeecode'     ------------- no need edit here -----------------------  declare @sql nvarchar(max) declare @present nvarchar(max) declare @absent nvarchar(max)   set @sql = 'select ' + @tablefieldid + '' set @present = '' set @absent = '' select      @present = @present + ' case when ' + syscolumns.[name] + ' = ''p'' 1 else 0 end + ' + char(10) + char(13),     @absent = @absent + ' case when ' + syscolumns.[name] + ' = ''a'' 1 else 0 end + ' + char(10) + char(13) sysobjects inner join syscolumns on sysobjects.id = syscolumns.id sysobjects.[name] = @tablename   -- remove last + set @present = left( @present, len(@present) - 4) + char(10) + char(13) set @absent= left( @absent, len(@absent) - 4) + char(10) + char(13)  set @sql = @sql + ', present =' +  @present + ', absent =' +  @absent +  'from ' + @tablename +  char(10) + char(13)    exec sp_executesql @sql

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