php - Return all elements from list that don't have a record. (MYSQL) -


i have list of feeds:

('feed1', 'feed2', 'feed3')

i have table feeds list of feeds, need find feeds in search list don't appear in database.

create table `feeds_filtered` (   `id` char(36) not null,   `url` varchar(255) not null,   ......   primary key (`id`) ) engine=myisam default charset=utf8;

for example feed1 , feed3 exist in table want feed 2 returned. please note: feeds table has feed4, feed5 etc don't want them returned either. feed2

i can write php script this, wondering if there easy way mysql?

thanks in adavnce!

you create temporary table, left join, records rhs of join null.


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