c# - How to get the maximum item ordered by two fields using a Linq expression? -

is possible result1 single linq expression? understand may not best practise know how out of curiousity.

result2 has different answer correct too. however, has complexity of o(nlogn) opposed o(n).

void main() {     a[] = new a[4]{new a(0,0,0),new a(1,1,0),new a(1,2,1),new a(1,2,0)};     /*     //grossly inefficient: replaced     var tmplist = a.where(x => (x.one == a.max(y => y.one)));            var result1 = tmplist.first(x => (x.two == tmplist.max(y => y.two)));     */     var maxonevalue = a.max(x => x.one);     var tmplist = a.where(x => (x.one == maxonevalue));     var maxtwovalueoftmplist = tmplist.max(x => x.two);     var result1 = tmplist.first(x => (x.two == maxtwovalueoftmplist));     //a: 1, 2, 1      var result2 = a.orderby(x => x.one)               .thenby(x => x.two)               .last();     //a: 1, 2, 0 }  class  {     public int one;     public int two;     public int three;     public a(int one, int two, int three)     {         this.one = one;         this.two = two;         this.three = three;     } } 

edit: have edited question , hence answers may not tally.

this query gives same result :

var result = a.orderbydescending(x => x.one + x.two)                       .first(); 

but items without max 'one' field.. 1 should work :

var result = a.orderbydescending(x => x.two)                .where(x => (x.one == a.max(y => y.one)))                .first();