python read output -

write program outputs first number within file specified user. should behave like:

enter file name: l11-1.txt
first number 20.

you need use file object method .read(1) read 1 character @ time, , string object method check if number. if there no number, expected behaviour is:

enter file name: l11-2.txt
there no number in l11-2.txt.

why reading 1 character @ time better algorithm calling .read() once , processing resulting string using loop?

i have files , correspond answers above im not sure how make output properly.

the code have far below:

    filenm = raw_input("enter file name: ")     datain=file(filenm,"r")  try:     c=datain.read(1)     result = []     while int(c) >= 0:     result.append(c)     c = datain.read(1)  except:     pass if len(result) > 0:     print "the first number is",(" ".join(result))+" . " else:     print "there no number in" , filenm + "." 

so far opens file , reads output no number if there one. can me ?

ok, you've been given instructions:

• read string input user
• open file given string
• .read(1) character @ time until first number or eof
• print number

you've got first , second parts here (although should use open instead of file open file), next? first thing work out algorithm: want computer do?