c - how to replace a char in char * -

total newbie here. trying replace character in char * program gives error

#include <stdio.h>  int main(int argc, char **argv) {     char *mystring ="love alweys better yoe";     int count = 1;      (count ;  count < 23; count++)     {          if ((mystring[count] == 0x65 )) //&& ((mystring[count+1] > 0x41) && (mystring[count+1] < 0x7a)))      {       mystring[count] = 0x45; //here occur freezing       printf ("%c\n", mystring[count]);        //break;     };     };      printf("%s\n",mystring);     return 0; } 

the

char *mystring ="love alweys better yoe" 

makes mystring read-only

you need copy string buffer before can change it

e.g.

char mystring[128]; strcpy( mystring , "love alweys better yoe" );