How to force a LocalJumpError on return in Ruby? -


my function bar gets block, , i'd run block without allowing return. how do modifying bar below, , keeping else, including foo, intact?

def bar()   yield end def foo()   bar     p "it"     return  # works. i'd localjumperror.   end end foo

well, localjumperror when try , pass block return proc (as opposed lambda).

you can away not changing foo except how it's called, if like

def bar()   proc.new end  def foo()   bar     p "it"     return   end end  foo[]

that gives localjumperror.

anyway, this article might help.

edit: return in proc return outer method, not anonymous method in block. might able set flag can check in bar see if returned prematurely:

bar_finished = false  def bar(&block)   proc = proc.new &block   l.call   bar_finished = true end

then, if return in block passed bar, bar_finished still false. not sure if adding non-local variable option, if so, track returns block , throw whatever exception want if happens.


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