php - How to extract year using preg_match -


i have textarea users enter details, want extract year textarea. problem users enter year in different ways.

some users input dates 1999 or '99 or september 99. how can use single regex string extract year.

this should work extracting mentioned dates out of text:

preg_match_all('/(^|\s+)(\d{4}|\'\d{2}|(january|february|march|april|may|june|july|august|september|october|november|december) \d{2})(\s+|$)/i', $text, $matches);

this came mind, (it gives user little more freedom):

preg_match_all('/(^|\s+)((january|february|march|april|may|june|july|august|september|october|november|december|jan|feb|mar|apr|may|jun|jul|aug|sep|oct|nov|dec)?(\s|\s?\')(\d{2}|\d{4}))(\s+|$)/i', $text, $matches);

all of above easier when parsed multiple expressions. why need single one?

if want parse string contains nothing else this, should use php's strtotime()-function.


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