bash recursive xtrace -


is there way run bash script x if x call executable bash script y y starts 'sh -eux'?

x.sh:

./y.sh

y.sh:

#!/bin/sh echo ok

it possible make subshell run using same shell options set in parent exporting shellopts environment variable.

in case x.sh , y.sh cannot edited, i'd create wrapper script exports shellopts before calling x.sh.

example:

#!/bin/sh # example x.sh calls y.sh ./y.sh

.

#!/bin/sh # example y.sh needs called using sh -eux echo $shellopts

.

#!/bin/sh -eux # wrapper.sh sets options sub shells export shellopts ./x.sh

calling x.sh directly shows -eux options not set in y.sh

[lsc@aphek]$ ./x.sh  braceexpand:hashall:interactive-comments:posix

calling via wrapper.sh shows options have propagated subshells.

[lsc@aphek]$ ./wrapper.sh  + export shellopts + ./x.sh + ./y.sh + echo braceexpand:errexit:hashall:interactive-comments:nounset:posix:xtrace braceexpand:errexit:hashall:interactive-comments:nounset:posix:xtrace

tested on gnu bash, version 3.00.15(1)-release. ymmv.


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