xslt - How to add @xml:base to my .xml files? -

i need stylesheet convert docbook xml files include xml:base element section tags. how go doing (since xml:base needs system , node info???)

input:

<section xmlns="http://docbook.org/ns/docbook" xml:id="voidvisit" version="5"> <title>void</title>   <section>   <title>screenshot</title>       <mediaobject>           <imageobject>               <imagedata fileref="screenshots/dialog.png" />           </imageobject>       </mediaobject>  </section> </section> 

output:

      ...       <section xml:id="void" version="5"            xml:base="file:/c:/projects/my/proj/trunk/spec/module/components/void.xml">      <title>void</title>      <section>         <title>screenshot</title>         <mediaobject>            <imageobject>               <imagedata fileref="screenshots/dialog.png"/>            </imageobject>         </mediaobject>      </section>      ... 

in xslt 2.0 (xpath 2.0) functions static-base-uri() , base-uri() can used purpose.

here working example:

<xsl:stylesheet version="2.0"  xmlns:xsl="http://www.w3.org/1999/xsl/transform">  <xsl:output omit-xml-declaration="yes"/>     <xsl:template match="/">      <doc xml:base="{base-uri()}"/>     </xsl:template> </xsl:stylesheet> 

when transformation applied, wanted result produced:

<doc xml:base="file:/c:/cvs-ddn/fxsl-xslt2/data/marrowtr.xml"/> 

so, complete transformation in case is:

<xsl:stylesheet version="2.0"  xmlns:xsl="http://www.w3.org/1999/xsl/transform"  xmlns:d="http://docbook.org/ns/docbook">  <xsl:output omit-xml-declaration="yes"/>      <xsl:template match="node()|@*">       <xsl:copy>          <xsl:apply-templates select="node()|@*"/>       </xsl:copy>     </xsl:template>      <xsl:template match="/d:section">      <xsl:copy>        <xsl:attribute name="xml:base" select="base-uri(/)"/>        <xsl:apply-templates select="node()|@*"/>      </xsl:copy>     </xsl:template> </xsl:stylesheet> 

in xslt 1.0 solution is pass base-uri external parameter (global xsl:param>) transformation.