C - differentiate between 0 and \0 in integer array -

possible duplicate:
nul terminating int array

i'm trying print out elements in array:

int numbers[100] = {10, 9, 0, 3, 4}; printarray(numbers);  

using function:

void printarray(int array[]) {     int i=0;     while(array[i]!='\0') {         printf("%d ", array[i]);         i++;     }     printf("\n"); } 

the problem of course c doesn't differentiate between 0 element in array , end of array, after it's 0 (also notated \0).

i'm aware there's no difference grammatically between 0 , \0 looking way or hack achieve this:

10 9 0 3 4 

instead of this

10 9 

the array this: {0, 0, 0, 0} of course output still needs 0 0 0 0.

any ideas?

don't terminate array value in array.

you need find unique terminator.

since didn't indicate negative numbers in array, recommend terminating -1:

int numbers[100] = {10, 9, 0, 3, 4, -1}; 

if doesn't work, consider: int_max, or int_min.

as last resort, code sequence of values guaranteed not in array, such as: -1, -2, -3 indicates termination.

there nothing "special" terminating 0 or \0. terminate whatever works case.

---

if array can hold values in order, terminator isn't possible, , have keep track of length of array.

from example, like:

int numbers[100] = {10, 9, 0, 3, 4}; int count = 5; int i;  for(i=0; i<count; ++i) {     // numbers[i] }