c++ - Ambiguous call to a function -


i have 4 functions: 

template<class exception,class argument>  void allocate_help(const argument& arg,int2type<true>)const;   template<class exception,class argument>  std::nullptr_t allocate_help(const argument& arg,int2type<false>)const;   template<class exception>  void allocate_help(const exception& ex,int2type<true>)const;   template<class exception>  std::nullptr_t allocate_help(const exception& ex,int2type<false>)const;

but when call: 

allocate_help<std::bad_alloc>(e,int2type<true>()); //here e of std::bad_alloc type

i'm getting error:
error 3 error c2668: ambiguous call overloaded function why?

because call matches both:

template<class exception,class argument>  void allocate_help(const argument& arg,int2type<true>)const;

with exception = std::bad_alloc , argument = std::bad_alloc (argument automatically deduced), and:

template<class exception>  void allocate_help(const exception& ex,int2type<true>)const;

with exception = std::bad_alloc. hence ambiguity of call.

also think compiler should output matching function after error line, answer question yourself.


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